Dev|il
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最新评论
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leelege：
让一切GenericDao都去死吧
自己写的一个Hibernate CURD的封装 -
liuxuejin：
不用泛型的飘过，个人觉得没有什么必要，因为增删查的代码（简单的 ...
自己写的一个Hibernate CURD的封装 -
java113096：
finallygo 写道icanfly 写道ricoyu 写道 ...
自己写的一个Hibernate CURD的封装 -
jiluo093：
http://jiluo093.iteye.com/blog/ ...
自己写的一个Hibernate CURD的封装 -
piao_bo_yi：
Dev|il 写道yin_bp 写道Dev|il 写道dnst ...
自己写的一个Hibernate CURD的封装
文章列表
HDU2100Lovekey
- 博客分类：
- 算法设计
Lovekey
Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 2812 Accepted Submission(s): 929
Problem Description
XYZ-26进制数是一个每位都是大写字母的数字。 A、B、C、…、X、Y、Z 分别依次代表一个0 ~ 25 的数字，一个 n 位的26进制数转化成是10进制的规则如下
A0A1A2A3…An-1 的每一位代表的数字为a0a1a2a3…an-1 ，则该XYZ-2 ...
Reversi
Time Limit: 5000/2000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 591 Accepted Submission(s): 251
Problem Description
Reversi, also called Othello, is a two-sided game.
Each of the two sides corresponds to one player; they are referred to here as li ...
Tempter of the Bone
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 26363 Accepted Submission(s): 7218
Problem Description
The doggie found a bone in an ancient maze, which fascinated him a lot. However, when he picked it up, the maze bega ...
#include <iostream>
using namespace std;
const int _N = 10000;
int d[_N], p[_N];
bool flag[_N];
int n;
void dfs(int pos)
{
int i;
if(pos == n)
{
for(i = 0; i < n; i++)
cout<<d[i]<<" ";
cout<<endl;
return;
}
for(i = 0; i < n; ...
连连看
Time Limit: 20000/10000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 6496 Accepted Submission(s): 1660
Problem Description
“连连看”相信很多人都玩过。没玩过也没关系，下面我给大家介绍一下游戏规则：在一个棋盘中，放了很多的棋子。如果某两个相同的棋子，可以通过一条线连起来（这条线不能经过其它棋子），而且线的转折次数不超过两次，那么这两个棋子就可以在棋盘上消去。不好意思，由于我以前没有玩 ...
Number Sequence
Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 3450 Accepted Submission(s): 1555
Problem Description
Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1], b[2], ...... , b[M] (1 <= M <= 10000, 1 < ...
c实现
#include <iostream>
using namespace std;
//串的模式匹配算法
//返回字串t在主串s中第pos个字符后的位置,若不存在则返回0, 返回的位置可以是0
int Index(char s[], char t[], int pos)
{
int slen = strlen(s), tlen = strlen(t);;
int i = pos, j = 0;
while(i < slen && j < tlen)
{
if(s[i] == t[j])
{
i++;j ...
HDU1097A hard puzzle
- 博客分类：
- 算法设计
A hard puzzle
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 13911 Accepted Submission(s): 4872
Problem Description
lcy gives a hard puzzle to feng5166,lwg,JGShining and Ignatius: gave a and b,how to know the a^b.everybody objects to this ...
串的顺序实现
串的顺序结构实现有弊端:
1.串的最大长度固定
2.当串的长度超过MAXSTRLEN时,采用截尾法处理,这种方法不仅在求串的连接时可能发生,还在串的插入,置换也有可能发生.
#include <iostream>
using namespace std;
#define MAXSTRLEN 255 //用户可以在255以内定义最大串长
#define TURE 1
#define FALSE 0
#define ERROR 0
#define OK 1
typedef unsigned char SString[MAXSTRLEN + 1]; //0号 ...
Let the Balloon Rise
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 31804 Accepted Submission(s): 10554
Problem Description
Contest time again! How excited it is to see balloons floating around. But to tell you a secret, the judges' favor ...
继上篇文章 直接贴代码
#include <iostream>
using namespace std;
#define ElemType int
const int INIT_SIZE = 100;
const int INCREMENT_SIZE = 10;
//缺点:浪费空间
class Queue{
private:
int front;
int rear;
int queue_total_size;
ElemType *data;
public:
bool InitQueue(); //构造一个空队列
void Destory ...
队列的链式表示和实现
队列是一种先进先出的数据结构,和食堂排队打饭类似,在前面的先打到饭,而后来者只有等前面的打完饭,后面的才能进行
以下给出C++实现
#include <iostream>
using namespace std;
#define ElemType int
typedef struct QNode{
ElemType data;
struct QNode *next;
}Node, *NodePtr;
//72
//链队列
class Queue{
private:
NodePtr front; //队头
NodePt ...
Treasure the new start, freshmen!
Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 4758 Accepted Submission(s): 1543
Problem Description
background:
A new semester comes , and the HDU also meets its 50th birthday. No matter what's your majo ...
HDU2251Seinfeld
- 博客分类：
- 算法设计
Seinfeld
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 736 Accepted Submission(s): 381
Problem Description
I’m out of stories. For years I’ve been writing stories, some rather silly, just to make simple problems look difficult ...
#include <iostream>
using namespace std;
#define ElemType int
typedef struct LNode{
ElemType data;
struct LNode *next;
}Node;
//链栈
class ListStack{
private:
Node *head;
int list_stack_size;
Node * curr;
public:
ListStack()
{
list_stack_size = 0;
head = curr = NUL ...